130=x^2-x

Solution for 130=x^2-x equation:

130=x^2-x

We move all terms to the left:

130-(x^2-x)=0

We get rid of parentheses

-x^2+x+130=0

We add all the numbers together, and all the variables

-1x^2+x+130=0

a = -1; b = 1; c = +130;
Δ = b2-4ac
Δ = 12-4·(-1)·130
Δ = 521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{521}}{2*-1}=\frac{-1-\sqrt{521}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{521}}{2*-1}=\frac{-1+\sqrt{521}}{-2}
$